http://news.bbc.co.uk/2/hi/science/nature/6589157.stm Looks like there would be heaps of twisties! New 'super-Earth' found in space

The higher gravity might make cornering interesting You seriously wouldn't want to drop your bike (or pick it up afterwards) Even assuming your body could cope

5 times the mass. That means a gravity of around 50m/s... A 13 day orbit, (I wonder what it's rotation is like?) With those numbers the chance of life would likely be remote. At least anything more advanced than single cell, or colony sludge. But it does show that Ã¢â‚¬Å“EarthlikeÃ¢â‚¬ planets are not impossible to find

Not correct. Surface gravity is a function of mass and planetary diameter. The larger the planet is dimensionally the more dispursed the effects of the surface gravity. Even though the planet is 5 times as massive. It is spread out over a much greater radial distance. Also it is important to note the mass distributiuon of the planet (eg. does it have an iron core etc.). It is likely to have a SG of around 1.5 to 2.3 g's. Still a very lethargic planet to get around on.

1 light year = 9.460584 * 10^12 km 20.5 light years = 193,940,832,200,000 kms avg 250 km / tank = 775,763,328,800 fill ups to fill up a 10l tank at 1.50 per litre = $11,636,449,9332,000 one way At a top avg speed of 250km/hr it will take you 88,506,939 years :grin: :grin:

Work that out in todays dollars! NPV of a dollar in todays value based on a time span of 88 million years

[quote="pro-pilot]Not correct. Surface gravity is a function of mass and planetary diameter. The larger the planet is dimensionally the more dispursed the effects of the surface gravity. Even though the planet is 5 times as massive. It is spread out over a much greater radial distance. Also it is important to note the mass distributiuon of the planet (eg. does it have an iron core etc.). It is likely to have a SG of around 1.5 to 2.3 g's. Still a very lethargic planet to get around on.[/quote] 5 times the mass and 1.5 times the diameter. Lets do the maths placing that whole mass at the extremity of the diameter difference. F m/s^2 F 5/1.5^2 =5/2.25 =2.2.. Now we know that A) The mass is not all at this extremity That the core will be denser and is far closer. So you are correct that it will be less than 5 times the gravity, but it will be far more than 1.5SG and I would be willing to say noticeably larger than 2.3SG Maths simplified because I CBF working it out more accurately (Brain is still on holiday)

Agree Falcon. g = GM/r^2 Using earth as the reference unit of 1 g = 1 x 5 / 1.5 ^2 = 2.2 However. The distribution of mass could be 60% in 60% of the diameter. Effectively reducing this to about 2.0 g's? (limited information here, so best estimate). Would still be crushing.

Well lets assume you have one at every tank fill up. and they are about $3 each... 775,763,328,800 stops * $3 = $2,327,289,986,400

Well if ya wanna get stupid about it. In space you will not keep a constant speed. You will keep accelerating. You would need to re-fill (that time you will have a constant velocity) but until you reach mid-point (10.25 ly then turn around to decelerate).